Recursive
We swap the children recursively, bottom-up.
Time: , space:
.
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def invertTree(self, root: Optional[TreeNode]) -> Optional[TreeNode]:
if not root:
return None
if not root.left and not root.right:
return root
left_subtree = self.invertTree(root.left)
right_subtree = self.invertTree(root.right)
root.left = right_subtree
root.right = left_subtree
return root
Or, top-down:
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def invertTree(self, root: Optional[TreeNode]) -> Optional[TreeNode]:
if not root:
return None
root.left, root.right = root.right, root.left
self.invertTree(root.left)
self.invertTree(root.right)
return root
Iterative
With stack, we simulate top-down swaps.
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def invertTree(self, root: Optional[TreeNode]) -> Optional[TreeNode]:
if not root:
return None
stack = [root]
while stack:
u = stack.pop()
stack.extend( c for c in (u.left, u.right) if c )
u.left, u.right = u.right, u.left
return root
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