In each iteration of BFS, we process the entire level.
Time: , space:
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# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def levelOrder(self, root: Optional[TreeNode]) -> List[List[int]]:
if not root:
return []
all_levels = []
q = deque([root])
while q:
level_len = len(q)
level = [0] * level_len
for i in range(level_len):
u = q.popleft()
level[i] = u.val
q.extend(c for c in (u.left, u.right) if c)
all_levels.append(level)
return all_levels
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